If $p \to ( \sim p\,\, \vee \, \sim q)$ is false, then the truth values of $p$ and $q$ are respectively .
$T, F$
$F, F$
$F, T$
$T, T$
The contrapositive of $(p \vee q) \Rightarrow r$ is
$\sim p \wedge q$ is logically equivalent to
For any two statements $p$ and $q,$ the negation of the expression $p \vee ( \sim p\, \wedge \,q)$ is
Given the following two statements :
$\left( S _{1}\right):( q \vee p ) \rightarrow( p \leftrightarrow \sim q )$ is a tautology.
$\left( S _{2}\right): \sim q \wedge(\sim p \leftrightarrow q )$ is a fallacy.
Then
The negative of the statement $\sim p \wedge(p \vee q)$ is